shell script: remove everything behind .'s

[laborspy]

Does anyone know how to remove everything and including the .'s in a shell script. Right now I can remove the .'s but I don't know how to delete the other numbers.

Val = `echo $1 | sed "s/\.//g"`

[chirpy]

If you mean that you want to remove everything after the dot, then, if the regex follows the perl usage, the following should work:

Val = `echo $1 | sed "s/\..*//g"`